What is the area of a sector with a central angle of 2π/9 radians and a radius of 16.7 ft?

First, we determine the area of the whole circle that can be calculated through the equation,
                                           A = πr²
Substituting,
                                          A = π(16.7 ft)² = 278.89π ft²
Then, we multiply the area obtained by the ratio of the given angle to the whole revolution.
                        Area of the sector = ((2π/9)/2π) x 278.89π ft²
                                                        = 30.99π ft²
Thus, the area of the sector is approximately 30.99π ft².

I’m not sure what it is i sorry : ((

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