Calculate:
a) (-2)⁻³ × 0,8+(-1)⁵+(-19+2005)⁰;
b)-0,(6)+0,1(6)-0,6;
+3² ˣ2) : (-5)⁷+(-17+15) ˣ (-1)³.
! i give in: 50 puncte: *

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: