What is the solution set for this linear-quadratic system of equations?
y = x2 − x − 12
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Mathematics, 17.01.2020 13:31 penelope0
What is the solution set for this linear-quadratic system of equations?
y = x2 − x − 12
y − x − 3 = 0
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The general form of the quetion of a circle is ax^2+by^2+cx+dy+e=0 where a=b=0 if the circle has a radius of three units and the center lies on the y axis which set of values of a, b, c, d, and e might correspond to the circle
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