David wondered if the temperature outside affects his gas mileage. he recorded the temperature and his gas mileage over the last few months. his data is shown below.
what can he conclude from his data?
a the hotter the temperature, the better his gas mileage.
b the hotter the temperature, the worse his gas mileage.
c there is no relationship between the temperature and his gas mileage.
d the cooler the temperature, the better his gas mileage.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v