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The number of bacteria n at a certain time t is given by n = 100et /10, when there are 100 bacteria at time t = 0 hours. find how many hours t it takes for the bacteria to double (that is, increase from 100 to 200 bacteria). [use either ln(2) ≈ 0.7 to approximate your answer as appropriate.]
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The number of bacteria n at a certain time t is given by n = 100et /10, when there are 100 bacteria...
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