Aprofessor gives his students the choice of 7 assignments .
each student has to complete 4 of the 7 assignments .
how many combinations of the 4 assignments are possible !
a 11
b 45
c 28
d 35

35

Step-by-step explanation:

nCr = n!/(n-r)!r!

7C4 = 7!/(7-4)!4!

=7 × 6 × 5 ×4! / 3!4!

4! at the numerator will cancel that of the denominator

= 7×6×5 / 3!

=7×6×5 / 3×2

= 7×6×5 / 6

the 6 at the numarator will cancel that of the denominator

=7×5

=35

Therefore; 7C4 = 35

hello umm i don't understand your question can you explain it more pls

step-by-step explanation:

step-by-step explanation: