Mathematics, 27.11.2019 18:31 jellyangie1

At monroe high school, 62% of all students participate in after school sports and 11% participate in both after school sports and student council. what is the probability that a student participates in student council given that the student participates in after school sports?

Answers: 3

Show answers

Answers

Hey there!

Before you start solving anything, you need to identify which situation you want to call event A and which you want to call event B. I usually just do it in the order of the events as they're given to me in the question, so:

A = Student participates in student council
B = Student participates in after school sports

Any problems that contain the word "given" in the question portion will want you to refer to P(A | B) = P(A ∩ B)/P(B). P(A | B) literally means "probability of event A, given that event B has occurred." P(A ∩ B) is the probability of event A and B happening, and P(B) is just the probability of event B happening. We've been given all of that, so:

P(A | B) = P(A ∩ B)/P(B)
P(A | B) = 11% / 62%
P(A | B) = 0.11 / 0.62
P(A | B) = 0.18

There will be about an 18% chance that a student participates in student council, given that the student participates in after school sports.

Hope this helped you out! :-)

Answer from: Lnjayy

Answer with Step-by-step explanation:

At Monroe High School, 62% of all students participate in after school sports and 11% participate in both after school sports and student council.

A: students participate in after school sports

P(A)=0.62

B:students participate in student council

A∩B:students participate in both after school sports and student council.

P(A∩B)=0.11

B/A: student participates in student council given that the student participates in after school sports

baye's theorem says that

P(A∩B)=P(B/A)×P(A)

0.11=P(B/A)×0.62

⇒ P(B/A)=0.18

Hence, probability that student participates in student council given that the student participates in after school sports is:

0.18

Answer from: Quest

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

Answer from: Quest

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2 = -20

divide by -2 on each side

-2x^2 /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

Another question on Mathematics

Mathematics, 21.06.2019 15:20

Acourgette seed and a pumpkin seed is planted p(courgette seed germinates) 4/5 and p(pumpkin seed germinates) = 1/6 what is the probability that both seds germinate

Answers: 2

Answer

Mathematics, 21.06.2019 17:00

Yosef can eat 21 jamuns while rose can eat just 15 . complete the blank. yosef can eat % more jamuns than rose.

Answers: 1

Answer

Mathematics, 21.06.2019 18:00

Henry is an avid reader, he devours 90 pages in half an hour how many pages has henry read per minute?

Answers: 1

Answer

Mathematics, 21.06.2019 20:00

Solve for x and y a x= 13.3 y= 16.7 b x= 23.3 y= 12.5 c x= 7.5 y= 16.7 d x=7.5 y= 12.5