Find the volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm.
a. 11,520 cm3
b. 23,040 cm3
c. 7,680 cm3
d. 768 cm3

The volume of a square pyramid can be derived from the expression that the volume of an object is equal to the product of the area of the base times its height. For a square pyramid, it can be simplified as V = a^2(h)/3 where a is the side of the square base and h is the height. However, we are given the slant height. The equation would be:

V = a^2(h)/3

s^2 = (a/2)^2 + h^2     where s is the slant height
h = √( s^2 - (a/2)^2)
h = √( 26^2 - (48/2)^2)= 10

V = 48^2(10)/3 = 7680 cm^3 --> OPTION C

The solution to the system of equations (-2,2)