From a boat on the lake, the angle of elevation to the top of a cliff is 26°1'. if the base of the cliff is 205 feet from the boat, how high is the cliff (to the nearest foot)?

Let the distance of the cliff from the boat be y and height of the top of the cliff be x.

As per the statement:

From a boat on the lake, the angle of elevation to the top of a cliff is 26°1'. If the base of the cliff is 205 feet from the boat.

⇒y = 205 feet,

We have to find the high is the cliff i,e x.

Using tangent ratio:

See the diagram as shown below:

Opposite side = x feet

adjacent side = 205 feet

Using conversion:

then;

Substitute these values we have;

Multiply both sides by 205 we have;

ft

Therefore, 100 ft high is the cliff(to the nearest foot)

deez nu tz

step-by-step explanation:

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.