Find all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π. (enter your answers as a comma-separated list.)

All the possible values of x such that are: and this can be evaluated by using the trignometry properties.

Given :

All possible values of x can be determine by using trignometry properties. According to trignometry properties:

If than  .

Now put the values of which is 2x and which is x in above expression.

But the above solution is the general solution, the question ask the value of x between 0 and .

Therefore, at k = 0:

at k = 1:

at k = 2:

So, all the possible values of x such that are:

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the answer is. -82562234434584

step-by-step explanation: