Arecent survey shows that the probability of a college student drinking alcohol is 0.6. further, given that the student is over 21 years old, the probability of drinking alcohol is 0.8. it is also known that 30% of the college students are over 21 years old. what is the probability of drinking alcohol and being over 21 years old? 0.66 0.36 0.24 0.42

0.24

Step-by-step explanation:

These events are not mutually exclusive; this means they can happen at the same time.

For two events A and B that are not mutually exclusive,

P(A and B) = P(A) * P(B|A)

Let A be the event "over 21 years old" and B be the event "drinks alcohol".  

The probability that a student is over 21 years old is 0.3; this is because 30% of the students are over 21 years old.

The probability that a student drinks alcohol given they are over 21 is 0.8.

This gives us

P(A and B) = 0.3(0.8) = 0.24

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

she was supposed to add the hours(38.5) and multiply the amount of money she earned(7.50) resulting in $288.75 .

correct me if i'm wrong and if it is i'm truly sorry.