URGENT Find Surface Area of triangular shown.
(If you can please explain, thank you!!)

A) 264
B) 300
C) 240
D) 272

For what value of jn is mn parallel to kl

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Tan198=asin164=? how to solve this? ?