What are the values of a, b, and c in the quadratic equation 0 = one-halfx2 – 3x – 2? a = one-half, b = 3, c = 2 a = one-half, b = –3, c = –2 a = one-half, b = 3, c = –2 a = one-half, b = –3, c = 2

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

answer: (3,11) is your answer.

the answer is  

a.

4,624π mm2

step-by-step explanation: