If 12 men complete a piece of work in 10 days in how many days would 15 men complete the same work​

Step-by-step explanation:

number of men =12

time taken = 10 days

time taken to complete the work by 15 men = 12÷10=1.2

= 1.2 ×15 = 18

therefore, 18 days is taken to complete the work by 15 men

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.