Trigonometry Solve the entire triangle. Round sides to the nearest tenth.

A= 104 degrees, a=13, C = 27 degrees

A=
a=
B =
b=C=
c=

lowercase= sides Uppercase= angles

A=104 degrees

a=13

B=49 degrees

b=10.11

C=27degrees

c=6.08

Step-by-step explanation:

B=180.00∘−A−C=180.00∘−104.00∘−27.00∘=49.00∘b=sin(B)⋅asin(A)=sin(49.00∘)⋅13.00sin(104.00∘)=10.11c=sin(C)⋅asin(A)=sin(27.00∘)⋅13.00sin(104.00∘)=6.08

it has to have an angle of 90 degrees

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10