Find the area of the following triangle: 17 9 14 10 Note: Figure not to scale.​

I believe 76.5 is the area to the triangle above.

76.5

Step-by-step explanation:

the area is half the base× tge height so 1/2 (17)×9

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

c

step-by-step explanation: