17) (x - 1)? +(y - 8) = 4
A) x2 + y2 - 2x - 16y +61 = 0
B) 5x2 + y2 - 2x - 16y - 61 = 0
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Mathematics, 18.05.2021 20:10 annaharmon693
17) (x - 1)? +(y - 8) = 4
A) x2 + y2 - 2x - 16y +61 = 0
B) 5x2 + y2 - 2x - 16y - 61 = 0
C) x2 + y2 + 16x +2y + 61 = 0
D) x² + y2 +61 - 16y= 0
Answers: 3
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