Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution set of this problem?
(-0, -21)
(-00,-21]
[-21, +00)
(21, +00)

let the number be x

5(x+27)>6(x+26)

5x+135>6x+156

5x-6x>135-156

-x>-21

×<21

(21,+00)

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}