What is an equation of the line that passes through the points (0, -3)(0,−3) and (-5, 3)(−5,3)?

y = 6/5 x -3

Step-by-step explanation:

Standard equation of a line is expressed as;

y = mx+b

Slope m = y2-y1/x2-x1

Given the coordinates  (0, -3)and (-5, 3)

Slope m = 3-(-3)/-5-0

Slope m = 6/5

Since the line cuts the y axis at y = -3, hence b = -3

GEt the required equation;

Recall that y = mx+b

y = 6/5 x + (-3)

y = 6/5 x -3

This gives the required equation

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