Answer with no links, and work shown if you can. It is given that quadrilateral DEFG is inscribed in circle P. Because a circle measures 360 degrees, mEFG + mGDE = 360 degrees. By the_,1/2mEFG+1/2mGDE=180 degrees. By the inscribed angles theorem,_=1/2 mGDE and _=1/2mEFG. This means m

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

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