The proportion of adults who own a cell phone in a certain Canadian city is believed to be 65%. Forty adults are to be selected at random from the city. Let Xbe the number in the sample who own a cell phone. Under the assumptions given, the distribution of X is A. Bin(40,0.65)
B. N(26,14)
C. Bin(40,26)
D. N(40,14)

A. Bin(40,0.65)

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a cell phone, or they do not. The probability of an adult having a cell phone is independent of any other adult having a cell phone. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

In function of its parameters, the distribution is written as: Bin(n,p).

The proportion of adults who own a cell phone in a certain Canadian city is believed to be 65%

This means that

Forty adults are to be selected at random from the city.

This means that .

Thus, we have Bin(40,0.65), and the correct answer is given by option A.

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

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