How do I solve for the measures of the the interior angles of a polygon

Step-by-step explanation:

To solve for the interior angles for a polygon,

subtract 2 from the number of sides then multiply with 180

i.e, (n-2)180

e.g, in the case of a triangle, (3-2)180 = 1*180 = 180

As for square, (4-2)180 = 2*180 = 360

Hope u understand.

Mark as the brainliest

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: