Mathematics, 25.05.2021 18:40 KrishnaBalaram1235

H(-4), h(0), h(4), h(8) h(x)={-(x+1)^2 + 7, x<2
{-1/3x, x>4

h(-4)=
h(0)=
h(4)=
h(8)=

$H(-4), h(0), h(4), h(8) h(x)={-(x+1)^2 + 7, x<2 {-1/3x, x>4 h(-4)= h(0)= h(4)= h(8)=$

Answers: 1

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H(-4), h(0), h(4), h(8) h(x)={-(x+1)^2 + 7, x<2
{-1/3x, x>4

h(-4)=
h(...

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