A rocket is launched from a tower . The height of the rocket , y in feet, is related to the time after launch, in seconds , by the given equation. Using this equation, find the maximum height reached by the rocket , to the nearest tenth of a foot. y=-16x^2+173x+140

A=16 b=173 c=140

Step-by-step explanation: The maximum/minimum of a parabola given by y = ax2 + bx + c is at the x =-b/(2a). Once you have that x you can plug it back into the equation to find the y value, which is the maximum/minimum height.

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

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step-by-step explanation: