A rectangular field is nine times as long as it is wide. If the perimeter of the field is 1700 feet, what are the dimensions of the field?

A) Write an equation you can use to answer the given question. Let w be the width of the field. Do not
solve the equation yet.

The equation is
X (Make sure you use the correct variable.)

B) Use your equation to find the dimensions of the field.

The width of the field is
x feet.
The length of the field is
x feet.

I. L = 10.35 feet

II. W = 93.15 feet.

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangular field = 1700 feet

Translating the word problem into an algebraic expression, we have;

W = 9L

Mathematically, the formula for the perimeter of a rectangle is;

P = 2(L + W)

A. To write an equation;

X = P = 2(L + W)

B. To find the dimensions of the field;

207 = 2(L + 9L)

207 = 2L + 18L

207 = 20L

L = 207/20

L = 10.35 feet

To find the weight;

W = 9L

W = 9 * 10.35

W = 93.15 feet.

Therefore, the width of the field is

93.15 feet and the length of the field is

10.35 feet.

536

step-by-step explanation:

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all