The ratio of green m&m's to yellow is 2:5 if there are only green and yellow m&ms in the bag what is the smallest number of m&ms possible

There are at least 7 M&M's in the bag, since if there were only 1 green M&M, there would be 2.5 blue M&Ms, which is impossible.

Step-by-step explanation:

Given that the ratio of green M&M's to yellow is 2: 5, if there are only green and yellow M&M's in the bag, to determine what is the smallest number of M&M's possible, the following calculation must be performed:

5/2 = 2.5

2/5 = 1 / 2.5

Therefore, there are at least 7 M&M's in the bag, since if there were only 1 green M&M, there would be 2.5 blue M&Ms, which is impossible.

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

hope this .

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