Question is in the image

(x +3)^2 + (y -3)^2 = 3^2

Step-by-step explanation:

Your first task is to find the center.

The longest possible line of the circle goes from (-3,0) to (-3,6)

So the center is at the midpoint of these two points.

The midpoint is at (-3 - 3)/2 , (6+ 0)/2 or (-3,3)

That gives you the center of the circle.

So far what you have is

(x +3)^2 + (y -3)^2 = r^2

Now the distance of the center to the bottom point is (-3,3) to (-3,0)

r^2 = (x2 - x1)^2 + (y2 - y1)^2

x2 = - 3

x1 = - 3

y2 = 3

y1 = 0

r^2 = (-3 - -3)^2 + (3 - 0)^2

r^2 = 3^2

The entire answer is

(x +3)^2 + (y -3)^2 = 3^2

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

step-by-step explanation:

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