Please help me : find equation of the circle

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(x - 5)^2 + (y - 4)^2 = 6^2

Step-by-step explanation:

The standard equation of a circle of center (h, k) and radius r is:

(x - h)^2 + (y - k)^2 = r^2.

Here we are given the center (5, 4) and the radius r =  6.

Substituting these values into the standard equation, we get:

(x - 5)^2 + (y - 4)^2 = 6^2

(x - 5)^2 + (y - 4)^2 = 6^2

Step-by-step explanation:

The standard equation of a circle of center (h, k) and radius r is:

(x - h)^2 + (y - k)^2 = r^2.

Here we are given the center (5, 4) and the radius r =  6.

Substituting these values into the standard equation, we get:

(x - 5)^2 + (y - 4)^2 = 6^2

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !