What do you wish to be?

John used linear combination to solve the system of equations shown. he did so by multiplying the first equation by -3 and the second equation by another number to eliminate the x-terms. what number did jonas multiply the second equation by? 4x-6y=23x+5y=11

Y=(x+3)(x-4)(x+1)^2 sulutions? multiplicity?

Factor the trinomial below. 12x^2 - 32x - 12 a. 4(3x+3)(x-1) b. 4(3x+1)(x-3) c. 4(3x+6)(x-2) d. 4(3x+2)(x-6)