Geometric stuff and please explain

Perimeter = Sum of the sides measures

Perimeter = | AB | + | AT | + | BT |

Perimeter = ( x + 3 ) + ( 4x ) + ( 2x + 2 )

40 = x + 4x + 2x + 3 + 2

Colect like terms

40 = ( 1 + 4 + 2 )x + ( 3 + 2 )

40 = 7x + 5

Subtract both sides - 5

40 - 5 = 7x + 5 - 5

35 = 7x

Switch sides

7x = 35

Divide both sides by 7

7x ÷ 7 = 35 ÷ 7

x = 5

AB = x + 3 = 5 + 3 》 AB = 8

AT = 4x = 4 × 5 》 AT = 20

BT = 2x + 2 = 2(5) + 2 ===》 BT = 12

According to the law of inequality in a triangle, the sum of any two random sides must be greater than the size of the other side which means :

AB + AT > BT

&

AB + BT > AT

&

AT + BT > AB

If the sides is true in the above inequalities, then those sides are able to form a triangle ;

But if even one of the above inequalities is violated, those sides will not be able to form a triangle.

8 + 20 > 12 ( Check )

8 + 12 > 20 ( Nope this inequlity violated )

Thus the measures of the sides can not represent the measures of the sides of a triangle .

And we're done ...

b

step-by-step explanation: