(PLEASE HELP/LAST QUESTION) Write an equation of a line that passes through (3, -1) and is parallel and perpendicular to y = 6x - 4

Parallel: y=6x-19

Perpendicular: y=-1/6x-0.5

Step-by-step explanation:

To be parallel to a line, the slope must be the same as the line. Then, you plug 3,-1 into y=6x, and add or subtract to balance the equation. You do the same to find the perpendicular line, but the slope must be the negative reciprocal of the line it is perpendicular to.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: