A certain quadratic function has x-intercepts at 2 and 3. What are the x-coordinates of its vertex? a)7/2
b)1/2
c)3/2
d)5/2

Explanation:

The parabola is symmetric around its vertex. This means that the roots are the same horizontal distance away from the vertex. Furthermore, we can apply the midpoint formula on the given roots to find the x coordinate of the vertex.

Find the midpoint of 2 and 3 to get (2+3)/2 = 5/2

Note: 5/2 = 2.5

what is the question here

step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine