Pam's eye-level height is 324 ft above sea level, and Adam's eye-level height is 400 ft above sea level. How much farther can Adam see to the horizon? Use the formula d = StartRoot StartFraction 3 h Over 2 EndFraction EndRoot, with d being the distance they can see in miles and h being their eye-level height in feet. 1 mi StartRoot 6 EndRoot mi 19 mi 19 StartRoot 6 EndRoot mi

B. StartRoot 6 EndRoot mi

√6 mi

Step-by-step explanation:

A. 1 mi

B. StartRoot 6 EndRoot mi

C.19 mi

D. 19 StartRoot 6 EndRoot mi

d = √(3h/2)

Where,

d = distance they can see in miles h = their eye-level height in feet

Pam:

h = 324 ft

d = √(3h/2)

d = √{(3 * 324)/2}

= √972/2

= √486

= √(81 * 6)

= √81 * √6

= 9√6 mi

Adam:

h = 400 ft

d = √(3h/2)

d = √{(3 * 400)/2}

= √1200/2

= √600

= √(100 * 6)

= √100 * √6

= 10√6 mi

How much farther can Adam see to the horizon?

Adam - Pam

= 10√6 - 9√6

= √6 mi

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!