For the graph of the inequality x - 2y >4, what is a value of x for a point that is on the boundary line and the axes?
0-2
04
-4
O2

Step-by-step explanation:

Explanation:

First, find two points on the line if you change the inequality to an equation.

For  

x

=

0

:  

0

+

2

y

=

4

2

y

=

4

2

y

2

=

4

2

y

=

2

or  

(

0

,

2

)

For  

y

=

0

:  

x

+

0

=

4

x

=

4

or  

(

4

,

0

)

We can plot these two points and draw a line through them to get the border of the inequality:

graph{(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)(x+2y-4)=0}

The line will be solid because the inequality operator has a "or equal to" clause in it. We can now shade the area to the right of the line because the inequality has a "great than" clause in it.

graph{(x+2y-4)>=0}

answer:

your answer is: c. 196 7/8 in^3.