People think that that babies are equally likely to be either boys or girls. Actually, about 51.3% of all babies are boys. If a family has two children (not twins), what is the chance both children are boys

26.32%

Step-by-step explanation:

The probability that both children are boys would be a sequence of events. Therefore, in order to calculate this we need to multiply the probability of the first baby being a boy with the probability of the second baby being a boy. Since the probability of any baby being a boy is 51.3%, we simply multiply this value in decimal form by itself.

51.3 / 100 = 0.513

0.513 * 0.513 = 0.263169 or 26.32%

i dont know

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.