A cubical water tank can contain 1000/125 cubic meters of water. Find the length of a side of the water tank.
2 meters 3 meters
1/2 meters
1/3 meters

2 meters.

Step-by-step explanation:

We know that a cube of sidelength L has a volume:

V = L^3

Here, we know that the volume of water that the cube can hold is:

(1000/125) m^3

Then the volume of our cube is exactly that:

V = (1000/125) m^3

Then we have the equation:

L^3 = (1000/125) m^3

Which we can solve for L

L = ∛((1000/125) m^3 ) = (∛1000/∛125) m

Where we used that:

∛(a/b) = ∛a/∛b

Solving the cubic roots, we get:

L = (10/5) m = 2m

The length of the side of the water tank is 2 meters.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐