Given Q(x) = 7x − 3 and P(x) = 7x3 − 3x2 + 42x − 27, find P(x) Q(x) . (Divide using long division.)

Complete question:

Given Q(x) = 7x − 3 and P(x) = 7x3 − 3x2 + 42x − 27, find P(x) ÷ Q(x) . (Divide using long division.)

The quotient = x²  + 6 and the remainder = - 9

Step-by-step explanation:

Given;

Q(x) = 7x − 3

P(x) = 7x³ − 3x² + 42x − 27

To divide P(x) by Q(x) using long division, we apply the following method;

                                      x²  + 6

                                  ---------------------------------

                  7x − 3   √ 7x³ − 3x² + 42x − 27

                               − (7x³ - 3x²)

                               -------------------------------------

                                               42x − 27

                                           − (42x  − 18)

                               ----------------------------------------

                                                       − 9

The quotient = x²  + 6 and the remainder = - 9

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

answer: i believe it’s 245.04

step-by-step explanation: