Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a? 1/9
9
-9
-1/9

Pls answer​

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

Step 1 : Convert the equations in slope intercept form of the line .

and ,

Step 2: Find the slope of the lines :-

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

And the slope of the second line is ,

Step 3: Multiply the slopes :-

Multiply ,

Multiply both sides by a ,

Divide both sides by -1 ,

Hence the value of a is 9 .

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1