In the similarity transformation of ∆ABC to ∆DFE, ∆ABC was dilated by a scale factor of [?], reflected across the [ ], and moved through the translaton [ ]. A(-4, -2), B(0,-2), C(0,-4). D(1,1), E(3,2), F(3,1).

A. 2
B. 1/2
C. 3
D. 1/3​

A. X-axis
B. Origin
C. Y-axis
D. x=2

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

whew you’re speaking a different language