What is the greatest counting number that divides 17, 25 and 41 and leaves the same remainder in each case?

The greatest counting number that divides 17, 25 and 41 and leaves the same remainder in each case is 8

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

answer4 to the second power is 16

and 4 to the third power is 64,