Elliot has been running a lawn care business since 2000. He cuts grass, trims, and weed whacks yards for his customers throughout the season. Each year, he has increased his fee by the same amount. The table shows what Elliot charged each customer for two given years of his business: Year Lawn Care Fee

2000 $750

2010 $1350

A. What is the rate of change and initial value for Elliot’s business? How do you know?

B. Write an equation in slope-intercept form to represent the fees that Elliot charges each year.

A: initial value: $750; rare of change: $60

B: y = 60t + 750

Step-by-step explanation:

Initial value = value when he started ( in 2000) =$ 750

Each year he add a constants to that value

'y' will be the amount he get after t years a amount increase each year

y = 750 + at

In 2010 his free = 1350

t = 2010 - 2000 = 10 year

y = 1350

y = 750 + at

1350 = 750 + 10 a

600 = 10a

a = 60

y = 750 + 60t ( his fee as a function of time)

In slope form: y = 60t + 750

He increases he fee by $60 a year.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]