A researcher believes that 9%9% of pet dogs in Europe are Labradors. If the researcher is right, what is the probability that the proportion of Labradors in a sample of 622622 pet dogs would differ from the population proportion by greater than 3%3%

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

(23*2)-12=x     x=34

step-by-step explanation:

answer:

your answer is: c. 196 7/8 in^3.

well what did you do it matters what you did : )

step-by-step explanation: