Acertain three-digit number equals fifteen times the sum of its digits. if its digits are reversed, the resulting number exceeds n by 396. the one’s digit is one larger than the sum of the other two. give a linear system of three equations whose three unknowns are the digits of n. solve the system and find n.

If the digits are a, b and c, the number n is 100a+10b+c

Here are the equations:

a number equals fifteen times the sum of its digits:

100a+10b+c = 15(a+b+c)

if its digits are reversed, the resulting number exceeds n by 396:

100a+10b+c+396 = 100c+10b+a

the one’s digit is one larger than the sum of the other two:

a+b+1 = c

Solving it gives you a=1, b=3, c=5, the number is 135.

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.