The quadratic equation y = - 16t^2+ 56t+ 2 represents the height of a projectile, y, in feet, at a particular time, t, in seconds.
For what interval or intervals of time will the projectile be above 26 feet?

0.5 < x < 3

or (0.5, 3)

Step-by-step explanation:

-16t² + 56t + 2 = 26

Subtract both sides by 26

-16t² + 56t + 2 = 26

                 -26   -26

-16t² + 56t - 24 = 0

Divide both sides by -8 to simplify

(-16t² + 56t - 24)/8 = 0/8

2t² - 7t + 3 = 0

Factor

(x - 3)(2x - 1) = 0

Do this to find the x's

x - 3 = 0

 + 3  +3

x = 3

2x - 1 = 0

    + 1  + 1

2x = 1

2x/2 = 1/2

x = 0.5

0.5 < x < 3

This means the intervals will have to be between 0.5 and 3 seconds

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

the surface area is 124cm²

step-by-step explanation:

length: 4cm

width: 9cm

height:   2cm