Can anyone please help I’ve been working on this one for awhile

x=8

<AQB= 40

<BQC=40

Therefore AQC = 40 + 40 = 80

Step-by-step explanation:

If QB is the angle Bisector of < AQC

Then, <AQB=<BQC (Reason: The angle bisector divides an angle in equal measurement)

So,

5x= 8x-24

24 = 8x - 5x

24= 3x

24 /3 = x

Therefore, x = 8

Then lets substitute

<AQB =5 x

5 ×8 = 40

--

<BCQ = 8x - 24

8×8-24

64-24= 40

(the angle AQB and angle BQC are equal)

Then <AQC= 40 +40 = 80

--

FINISH

---

ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga

step-by-step explanation:

right

step-by-step explanation: