Jessica was given the area and the length of the base of a triangle. A = 17.5 units, b = 5 units. She solved the formula for area for h to find the height of the triangle. Determine if Jessica solved the equation correctly and found the correct answer. If not, describe what mistake she made and solve the formula for h correctly and justify your steps. A = bh

A · b = h

(17.5) (5) = h

43.75 = h

The height of the triangle is 43.75 units.

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She messed up the equation, A= B x h, she changed it midway, and also, you need to add the one half to make the equation valid

Step-by-step explanation:

A=1/2 x b xh

17.5 = 1/2 x 5 x h

35=5h     (multiply both sides by 2 to get rid of one half)

35/5 = 5h/5

7=h

The height of the triangle is 7 units

Please mark me brainliest, it really helps!

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841