14) A rocket leaves a launcher at a height of 7 feet off the ground with an initial velocity of 144 feet per second. The equation describing the rocket's height after t seconds is h = -16t^2+ 144t + 7.
a) Find the maximum height reached by the rocket.
b) How many seconds does it take for the rocket to reach that height?

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation:

according to egenuity the answer is

step-by-step explanation:

d. 344.22

y=20x

: )

hope this

emily solved for a part when she should have solved for the whole. 875,000 should be the numerator of the equivalent ratio. 70 x 12,500 is 875,000. so the answer is 100 x 12,500 which is 1,250,000.