Isolate c
a=b(1/c-1/d)

c = b/(a + 1).

Step-by-step explanation:

a = b(1/c - 1/d)

Expand RHS by first finding LCM

a = b((d — c)/cd)

a = (bd — bc)/cd

Then cross multiply

acd = bd — cd

Collect the terms having c to the LHS

acd + cd = bd

Factorise cd out of LHS

( a+ 1)dc = bd

c = bd/(a + 1)d

c = b/(a + 1).

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

cant see photo

step-by-step explanation: