Consider red light with a wavelength of 692 nm in air that is incident onto two slits such that it gives diffraction fringes that are 1.00 mm apart on a screen at a distance l from the slits. if the screen is moved back by an additional 4.00 cm, the fringes become 1.20 mm apart. what is the separation between the slits?

The separation between slits is:

Explanation:

The distance between adjacent maxima is given by the following expression:

For the distance between maxima being 1mm (let's solve all this problem using milimeters) we have the following:

(1)

For the second condition in which the screen is moved 40 mm away we have the following:

(2)

Using equation 1 we can write:

Plugging the value of L in equation 2 brings us to

We could also as a bonus find L which is just

I'll leave that up to you! Good luck!

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia