The sum of 4 consecutive integers is 38. What is the greatest of these integers?

11

Step-by-step explanation:

let the consecutive integers be

n, n + 1, n + 2, n + 3 , then

n + n + 1 + n + 2 + n + 3 = 38 , that is

4n + 6 = 38 ( subtract 6 from both sides )

4n = 32 ( divide both sides by 4 )

n = 8

n + 1 = 8 + 1 = 9

n + 2 = 8 + 2 = 10

n + 3 = 8 + 3 = 11

The greatest of the integers is 11

the answer is 3/5

step-by-step explanation:

first divide 24 divided by 8 because that is the least common multiple

then divide 40 by 8

then you will get 3/5.

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)